7a^2-44a-35=(7a+5)(a+7)

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Solution for 7a^2-44a-35=(7a+5)(a+7) equation: 



7a^2-44a-35=(7a+5)(a+7)

We move all terms to the left:

7a^2-44a-35-((7a+5)(a+7))=0

We multiply parentheses ..

7a^2-((+7a^2+49a+5a+35))-44a-35=0



We calculate terms in parentheses: -((+7a^2+49a+5a+35)), so:

(+7a^2+49a+5a+35)

We get rid of parentheses

7a^2+49a+5a+35

We add all the numbers together, and all the variables

7a^2+54a+35

Back to the equation:

-(7a^2+54a+35)



We add all the numbers together, and all the variables

7a^2-44a-(7a^2+54a+35)-35=0

We get rid of parentheses

7a^2-7a^2-44a-54a-35-35=0

We add all the numbers together, and all the variables

-98a-70=0

We move all terms containing a to the left, all other terms to the right

-98a=70

a=70/-98

a=-5/7

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